RE: Riddle- Let's see how many will get it right! -
03-21-2002, 01:51 AM
>Alright folks take a shot.
>
>Three people walk into a hotel to get a
>room.It costs $30 for the room(one room
>for all 3),it then follows that they pay
>$10 each.
> After a while,the hotel manager
>decides to give the customers, a $5
>discount(all not each).He sends one of
>his employees upstairs with the 5 bucks
>but on his way upstairs, the latter
>decides to keep $2 'to make the sum
>divisible by the three".
> The three people consequently get a
>dollar each & of course,the employee
>keeps $2.This means that the three
>customers, now paid $9 each $(10-1)
> Oh dear Mashadites,the question
>to you is, if the three people paid $9
>each(total $27)
> and the hotel employee kept $2,WHAT
>HAPPENED TO ONE DOLLAR(since
>27+2=29).Wapi dollar?!
>J.K
The dollar hasnt disappeared you are deliberately confusing the matahematics here. You cannot add the $2 kept by the employee to the $27... thet is incorrect maths. You are supposed to subtract it instead.
So that the correct equation will be.
Initial sum($30) = Change of ($3) +($2) kept by employee + the "correct bill" ($25)
Subtract the change from both ends of the equation and it simplifies to....
Sum paid by guests ($27) = ($2) Kept by employee + the "correct bill" ($25)
SO FROM THE ABOVE... YOU IF YOU TAKE THE $2 TO THE OTHER SIDE ..YOU CANNOT ADD IT TO THE 27 INSTEAD YOU SUBTRACT IT TO GET THE ACTUAL BILL THEY SHOULD HAVE PAID. !!! (25)
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